Permutation Generator in C++

Problem Statement:-

Set A=(1,3, a, s, t, i} represent alphanumeric characters permitted to be used to set the password of length 4. Write C/C++ program to generate all possible passwords.

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Code:-

	#include<iostream>3
	using namespace std;
	class PermutationGenerator
	{
	char *set;
	int count=1;
	int start,terms,levels;
	public:
	void swap(char *a,char *b)
	{
	int temp;
	temp=*a;
	*a=*b;
	*b=temp;
	}
	void permute(char *s,int start,int terms,int l=0)
	{
	int i=0;
	if(l==levels)
	{
	cout<<count<<":";
	for(int i=0;i<=levels-1;i++)
	cout<<*(s+i);
	cout<<endl;
	count++;
	}
	else
	{
	for(int i=start;i<=terms;i++)
	{
	swap(s+start,s+i);
	permute(s,start+1,terms,l+1);
	swap(s+start,s+i);
	}
	}
	}
	PermutationGenerator(int t)
	{
	set=new char[t];
	start=0;
	terms=t;
	levels=0;
	}
	void getSet()
	{
	cout<<"ENter Letters: \n";
	for(int i=start;i<terms;i++)
	cin>>set[i]; // *(set+i);
	}
	void generatePermutations()
	{
	cout<<"\nENter Number of literals to be used: ";
	cin>>levels;
	if(levels<=terms)
	permute(set,start,terms-1);
	else
	cout<<"\nPermutaion Not possible. ";
	}
	};
	int main()
	{
	int t;
	cout<<"Enter Number of elements: ";
	cin>>t;
	PermutationGenerator p(t);
	p.getSet();
	p.generatePermutations();
	}

view raw Permutation.CPP hosted with ❤ by GitHub

Output:-